g(a)=3a2−14a
asked by guest on Apr 09, 2025 at 9:46 pm
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g(a)=1+ag\left(a\right)=1+ag(a)=1+a
g(a)=3ag\left(a\right)=3ag(a)=3a
g(a)=3a+2
f(a)=5-2a
g(a)=a+5a
g(a)=3a-2
g(1)=-8
g(x)=-2
g(a)=a
g(x)=2.6−3g\left(x\right)=2.6-3g(x)=2.6−3
