105p^2 + 18p -8 = 0 solve using factorization method
You asked:
Solve the equation \(105 \cdot {p}^{2} + 18 p - 8 = 0\) by factoring.
MathBot Answer:
$$\begin{aligned}0 &= 105 p^{2} + 18 p - 8\\&= 105 p^{2} + 18 p - 8\end{aligned}$$$$p \in \left\{- \frac{3}{35} + \frac{\sqrt{921}}{105}, - \frac{\sqrt{921}}{105} - \frac{3}{35}\right\}$$