Math Problem Solver

\[ \frac{1}{12} + 10 + 8 = \frac{217}{12} = 18.08\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{12}\), \(\frac{10}{1}\), and \(\frac{8}{1}\) is \(12\). \[ \begin{aligned} \frac{1}{12} + 10 + 8 &= \frac{1 \cdot 1}{12 \cdot 1} + \frac{10 \cdot 12}{1 \cdot 12} + \frac{8 \cdot 12}{1 \cdot 12} \\ &= \frac{1 + 120 + 96}{12} \\ &= \frac{217}{12} \end{aligned} \]