CRC = M(x)*xK mod G
To do the division, we convert M and G into polynomial form.
M(x) = x6+ x4+ x2+1, G(x) = x4+ x3+1
K = 4, => CRC is 4 bits wide.
M(x)*x4 = x10+ x8+ x6+ x4
Divide this by G(x) to get the CRC.
x6+ x5+ x
x4+ x3+1 |x10+ x8+ x6+ x4
x10+ x9+ x6
x9+ x8+ x4
x9+ x8+ x5
x5+ x4
x5+ x4+ x
X
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.