If π(π₯, π¦) = π₯
2
tanβ1
(
π¦
π₯
) β π¦
2
tanβ1
(
π₯
π¦
), then verify ππ₯π¦ = ππ¦π₯
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
If π(π₯, π¦) = π₯
2
tanβ1
(
π¦
π₯
) β π¦
2
tanβ1
(
π₯
π¦
), then verify ππ₯π¦ = ππ¦π₯
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.