y=tan^-1( $\sqrt{\}$ 1+cos^2x/2)/ $\sqrt{\}$ 1-cos^2x/2
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
y=tan^-1( $\sqrt{\}$ 1+cos^2x/2)/ $\sqrt{\}$ 1-cos^2x/2
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.