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pi*y=(arccos(x)-x*sqrt(1-x^2))
asked by
guest
on Mar 29, 2025 at 5:02 pm
You asked:
Investigate the equation:
π
y
=
arccos
(
x
)
−
x
1
−
x
2
\pi y = \arccos\left( x \right) - x \sqrt{1 - {x}^{2}}
π
y
=
arccos
(
x
)
−
x
1
−
x
2
.
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