3x + 5y + 8(1-x-y) = 7x + 6y + 5(1-x-y)
You asked:
Investigate the equation: \(3 x + 5 y + 8 \cdot \left(1 - x - y\right) = 7 x + 6 y + 5 \cdot \left(1 - x - y\right)\).
MathBot Answer:
The graph of \(3 x + 5 y + 8 \cdot \left(1 - x - y\right) = 7 x + 6 y + 5 \cdot \left(1 - x - y\right)\) is a line.
The x-intercept is \(\frac{3}{7}\).
The y-intercept is \(\frac{3}{4}\).
The slope of the line is \(- \frac{7}{4}\).
The slope-intercept form of the line is \(y = \frac{3}{4} - \frac{7 x}{4}\).
The line in standard form is \( - 7 x - 4 y + 3 = 0 \)