y= x⅔ + 0.9 sin (kx) √3-x²

asked by guest
on Nov 28, 2024 at 5:48 pm



You asked:

Investigate the equation: \(y = x\left( \frac{2}{3} \right) + 0.9 \cdot \sin\left( k x \right) \cdot \sqrt{3} - {x}^{2}\).

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