k=[sin(54)/( sin126\sqrt{sin126}+ $\sqrt{\(sin54)(sin36)}$ )]^{2}

asked by guest
on Nov 12, 2024 at 5:39 pm



You asked:

Solve the equation k=(sin⁡(54)sin⁡(126)+sin⁡(54)sin⁡(36))2k = {\left( \frac{\sin\left( 54 \right)}{\sqrt{\sin\left( 126 \right)} + \sqrt{\sin\left( 54 \right) \sin\left( 36 \right)}} \right)}^{2} for the variable kk.

MathBot Answer:

The solution is: k=sin⁡2(54)(sin⁡(126)+−sin⁡(36)−sin⁡(54))2≈0.17950555k = \frac{\sin^{2}{\left(54 \right)}}{\left(\sqrt{\sin{\left(126 \right)}} + \sqrt{- \sin{\left(36 \right)}} \sqrt{- \sin{\left(54 \right)}}\right)^{2}} \approx 0.17950555

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