(10/3) + (4/3)/(5k/3) = (2k/(k+1))-1

asked by guest
on Mar 21, 2025 at 5:19 pm



You asked:

Solve the equation 103+435k3=2kk+1−1\frac{10}{3} + \frac{\frac{4}{3}}{\frac{5 k}{3}} = \frac{2 k}{k + 1} - 1 for the variable kk.

MathBot Answer:

The 2 solutions to the equation are: k=−1110−424970≈−2.0312051k=−1110+424970≈−0.16879494\begin{aligned}k &= - \frac{11}{10} - \frac{\sqrt{4249}}{70} \approx -2.0312051\\k &= - \frac{11}{10} + \frac{\sqrt{4249}}{70} \approx -0.16879494\end{aligned}

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