cos(x) = 1,x

asked by guest
on Nov 24, 2024 at 10:22 am



MathBot Answer:

The principal value in 0xπ0 \le x \le \pi is x0x \approx 0



The complex solutions are: {2nπ  |  nZ}\left\{2 n \pi\; \middle|\; n \in \mathbb{Z}\right\}