cos(x) = 1,x
asked by guest on Nov 24, 2024 at 10:22 am
MathBot Answer:
The principal value in 0≤x≤π0 \le x \le \pi0≤x≤π is x≈0x \approx 0x≈0
The complex solutions are: {2nπ | n∈Z}\left\{2 n \pi\; \middle|\; n \in \mathbb{Z}\right\}{2nπ∣n∈Z}