1/7+1/14+1/28

asked by guest
on Mar 22, 2025 at 7:22 am



You asked:

Evaluate the expression: 17+114+128\frac{1}{7} + \frac{1}{14} + \frac{1}{28}

MathBot Answer:

17+114+128=14=0.25 \frac{1}{7} + \frac{1}{14} + \frac{1}{28} = \frac{1}{4} = 0.25


The sum can be computed by rewriting each term over a common denominator, where the least common denominator of 17\frac{1}{7}, 114\frac{1}{14}, and 128\frac{1}{28} is 2828. 17+114+128=1474+12142+11281=4+2+128=728=14 \begin{aligned} \frac{1}{7} + \frac{1}{14} + \frac{1}{28} &= \frac{1 \cdot 4}{7 \cdot 4} + \frac{1 \cdot 2}{14 \cdot 2} + \frac{1 \cdot 1}{28 \cdot 1} \\ &= \frac{4 + 2 + 1}{28} \\ &= \frac{7}{28} \\&= \frac{1}{4} \end{aligned}