y = x ^ 2 + 4x - 5

asked by guest
on Nov 17, 2024 at 7:46 am



You asked:

Investigate the equation: \(y = {x}^{2} + 4 x - 5\).

MathBot Answer:

The graph of the equation \(y = {x}^{2} + 4 x - 5\) is a parabola.


The coordinates of its vertex are: \(\left(-2, -9\right)\)

The coordinates of its focus are: \(\left(-2, - \frac{35}{4}\right)\)

The directrix has equation: \(4 y + 37 = 0\).

The parabola has parameterization: \[\begin{aligned}x\left(\theta\right) &= -2 + \theta\\y\left(\theta\right) &= -9 + \theta^{2}\end{aligned}\]