factorize $2x^{3}$ - $8x^{1}$ +$2yx^{2}$ - $8y^{1}$
You asked:
Factor the expression: \(\displaystyle 2 \cdot {x}^{3} - 8 \cdot {x}^{1} + 2 y \cdot {x}^{2} - 8 \cdot {y}^{1}\)
MathBot Answer:
The polynomial factors into the product: \[2 \cdot {x}^{3} - 8 \cdot {x}^{1} + 2 y \cdot {x}^{2} - 8 \cdot {y}^{1} = 2 \left(x - 2\right) \left(x + 2\right) \left(x + y\right)\]