1+sec theta divided by 1-sec theta equals to sin theta + tan theta divided by sin theta-tan theta

asked by guest
on Sep 22, 2024 at 5:20 am



You asked:

Solve the equation \(1 + \frac{\sec\left( θ \right)}{1} - \sec\left( θ \right) = \sin\left( θ \right) + \frac{\tan\left( θ \right)}{\sin\left( θ \right)} - \tan\left( θ \right)\) for the variable \(θ\).

MathBot Answer:


The complex solutions are: \[\left\{2 n \pi\; \middle|\; n \in \mathbb{Z}\right\}\]