8(6-r)=6(8-r)
You asked:
Solve the equation \(8 \cdot \left(6 - r\right) = 6 \cdot \left(8 - r\right)\) for the variable \(r\).
MathBot Answer:
The solution is: \[r = 0\]
\[\begin{aligned}48 - 8 r &= 48 - 6 r\\- 2 r &= 0\\r &= 0\end{aligned}\]