x^3-7x+6=
asked by guest on Mar 30, 2025 at 6:00 am
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MathBot Answer:
x3−7x+6=x3−7x+6\displaystyle {x}^{3} - 7 x + 6 = x^{3} - 7 x + 6 x3−7x+6=x3−7x+6
x3−7x+6=(x−2)(x−1)(x+3){x}^{3} - 7 x + 6 = \left(x - 2\right) \left(x - 1\right) \left(x + 3\right)x3−7x+6=(x−2)(x−1)(x+3)