$4^{x}$+ $2^{2x-3}$ = $\frac{ 9\}{8\}$
You asked:
Solve the equation \({4}^{x} + {2}^{2 x - 3} = \frac{9}{8}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = 0\]
$4^{x}$+ $2^{2x-3}$ = $\frac{ 9\}{8\}$
You asked:
MathBot Answer:
The solution is: \[x = 0\]