3(w+1)+4(2w+3)
asked by guest on Mar 21, 2025 at 4:40 am
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MathBot Answer:
3(w+1)+4(2w+3)=11w+15\displaystyle 3 \left(w + 1\right) + 4 \left(2 w + 3\right) = 11 w + 15 3(w+1)+4(2w+3)=11w+15
3(w+1)+4(2w+3)=11w+153 \left(w + 1\right) + 4 \left(2 w + 3\right) = 11 w + 153(w+1)+4(2w+3)=11w+15