\frac{-10x}{7}\div \frac{7y}{3}
asked by guest on Mar 25, 2025 at 4:23 pm
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MathBot Answer:
−(10x)77y3=−30x49y\frac{\frac{-\left( 10 x \right)}{7}}{\frac{7 y}{3}} = - \frac{30 x}{49 y}37y7−(10x)=−49y30x