solve(d^2-3d+2)y=x^2+3x+1

asked by guest
on Mar 21, 2025 at 8:31 pm



You asked:

Investigate the equation: (d2−3d+2)⋅y=x2+3x+1\left({d}^{2} - 3 d + 2\right) \cdot y = {x}^{2} + 3 x + 1.

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