-x^3 + 3x^2 + 4x - 12 = 0

asked by guest
on Mar 15, 2025 at 2:29 pm



You asked:

Solve the equation −x3+3x2+4x−12=0-{x}^{3} + 3 {x}^{2} + 4 x - 12 = 0 for the variable xx.

MathBot Answer:

The 3 solutions to the equation are: x=−2x=2x=3\begin{aligned}x &= -2\\x &= 2\\x &= 3\end{aligned}

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