0=-2+(((1)/(2)))^(x+1)
raiz
You asked:
Given \(0 = -2 + {\left( \frac{1}{2} \right)}^{x + 1}\) evaluate the expression \(r a i z\).
MathBot Answer:
The expression \(r a i z\) does not depend on the equation \(0 = -2 + {\left( \frac{1}{2} \right)}^{x + 1}\).