y'' - 4y' + 13y=18e^2xsin3x

asked by guest
on Sep 22, 2024 at 1:17 pm



You asked:

Investigate the equation: \(y^{\prime \prime} - 4 \cdot y^{\prime} + 13 y = 18 \cdot {e}^{2} \cdot x \cdot \sin\left( 3 x \right)\).

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