(m ^ { 3 } +3m ^ { 2 } -6) \div (m+3)
asked by guest on Mar 26, 2025 at 8:55 pm
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MathBot Answer:
m3+3m2−6m+3=m3+3m2−6m+3\displaystyle \frac{{m}^{3} + 3 {m}^{2} - 6}{m + 3} = \frac{m^{3} + 3 m^{2} - 6}{m + 3} m+3m3+3m2−6=m+3m3+3m2−6
m3+3m2−6m+3=m3m+3+3m2m+3−6m+3\frac{{m}^{3} + 3 {m}^{2} - 6}{m + 3} = \frac{m^{3}}{m + 3} + \frac{3 m^{2}}{m + 3} - \frac{6}{m + 3}m+3m3+3m2−6=m+3m3+m+33m2−m+36
