sin3A/sin2A

asked by guest
on Mar 31, 2025 at 2:54 pm



You asked:

Evaluate the expression: sin⁡(3A)sin⁡(2A)\frac{\sin\left( 3 A \right)}{\sin\left( 2 A \right)}

MathBot Answer:

sin⁡(3A)sin⁡(2A)=sin⁡(3A)sin⁡(2A)\frac{\sin\left( 3 A \right)}{\sin\left( 2 A \right)} = \frac{\sin{\left(3 A \right)}}{\sin{\left(2 A \right)}}

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