Math Problem Solver

\[ \frac{6}{4} + 248 = \frac{499}{2} = 249.5 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{6}{4}\) and \(\frac{248}{1}\) is \(4\). \[ \begin{aligned} \frac{6}{4} + 248 &= \frac{6 \cdot 1}{4 \cdot 1} + \frac{248 \cdot 4}{1 \cdot 4} \\ &= \frac{6 + 992}{4} \\ &= \frac{998}{4} \\&= \frac{499}{2} \end{aligned} \]