1/243 = 9^(x+1) + 3^x

asked by guest
on Apr 19, 2024 at 4:55 am

You asked:

Solve the equation \(\frac{1}{243} = {9}^{x + 1} + {3}^{x}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{\log{\left(- \frac{1}{18} + \frac{\sqrt{93}}{162} \right)}}{\log{\left(3 \right)}} \approx -5.0319802\]

asked 13 days ago

active 13 days ago