1/243 = 9^(x+1) + 3^x
You asked:
Solve the equation \(\frac{1}{243} = {9}^{x + 1} + {3}^{x}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{\log{\left(- \frac{1}{18} + \frac{\sqrt{93}}{162} \right)}}{\log{\left(3 \right)}} \approx -5.0319802\]
asked 13 days ago
active 13 days ago