i^(16k+3)=
asked by guest on Nov 26, 2024 at 7:15 am
You asked:
MathBot Answer:
i16k+3=i16k+3\displaystyle {i}^{16 k + 3} = i^{16 k + 3} i16k+3=i16k+3
i16k+3=−ii16k{i}^{16 k + 3} = - i i^{16 k}i16k+3=−ii16k
iii is the imaginary unit, defined as i2=−1i^2 = -1i2=−1.