i^(16k+3)=

asked by guest
on Nov 26, 2024 at 7:15 am



You asked:

Evaluate the expression: i16k+3{i}^{16 k + 3}

MathBot Answer:

Evaluated



i16k+3=i16k+3\displaystyle {i}^{16 k + 3} = i^{16 k + 3}


Expanded

i16k+3=ii16k{i}^{16 k + 3} = - i i^{16 k}


ii is the imaginary unit, defined as i2=1i^2 = -1.