i^(16k+3)=
You asked:
Evaluate the expression: \({i}^{16 k + 3}\)
MathBot Answer:
Evaluated
\(\displaystyle {i}^{16 k + 3} = i^{16 k + 3} \)
Expanded
\[{i}^{16 k + 3} = - i i^{16 k}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).
i^(16k+3)=
You asked:
MathBot Answer:
\(\displaystyle {i}^{16 k + 3} = i^{16 k + 3} \)
\[{i}^{16 k + 3} = - i i^{16 k}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).