𝟏𝟏𝒊(−𝟖𝒊 + 𝟏𝟎)
asked by guest on Mar 25, 2025 at 5:54 pm
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MathBot Answer:
11i(−(8i)+10)=11i(10−8i)\displaystyle 11 i \left(-\left( 8 i \right) + 10\right) = 11 i \left(10 - 8 i\right) 11i(−(8i)+10)=11i(10−8i)
11i(−(8i)+10)=88+110i11 i \left(-\left( 8 i \right) + 10\right) = 88 + 110 i11i(−(8i)+10)=88+110i
11i(−(8i)+10)=22i(5−4i)11 i \left(-\left( 8 i \right) + 10\right) = 22 i \left(5 - 4 i\right)11i(−(8i)+10)=22i(5−4i)
iii is the imaginary unit, defined as i2=−1i^2 = -1i2=−1.