𝑥 ′ − 5 𝑥 + 𝑦 ′ + 𝑦 = $e^{t}$
− 𝑥 ′ − 3 𝑥 + 𝑦 ′ + 3 𝑦 = $e^{t}$
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
𝑥 ′ − 5 𝑥 + 𝑦 ′ + 𝑦 = $e^{t}$
− 𝑥 ′ − 3 𝑥 + 𝑦 ′ + 3 𝑦 = $e^{t}$
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.