\frac{2}{t+1}\cdot -\frac{2}{\left(t+1\right)^2}
You asked:
Evaluate the expression: \(\frac{2}{t + 1} \cdot -\left( \frac{2}{{\left( t + 1 \right)}^{2}} \right)\)
MathBot Answer:
Evaluated
\(\displaystyle \frac{2}{t + 1} \cdot -\left( \frac{2}{{\left( t + 1 \right)}^{2}} \right) = - \frac{4}{\left(t + 1\right)^{3}} \)
Expanded
\[\frac{2}{t + 1} \cdot -\left( \frac{2}{{\left( t + 1 \right)}^{2}} \right) = - \frac{4}{t^{3} + 3 t^{2} + 3 t + 1}\]