V^2=2y^2+u^2
V=u+2y
You asked:
Solve the system of equations:\[\begin{aligned}{V}^{2} &= 2 \cdot {y}^{2} + {u}^{2}\\V &= u + 2 y\end{aligned}\]
MathBot Answer:
The system of equations has infinitely many solutions.
$$\begin{aligned}V &= u\\y &= 0\end{aligned}$$\(u\) is a free variable.