(x−1)÷(x^2+6x+9)

asked by guest
on Nov 24, 2024 at 8:28 pm



You asked:

Evaluate the expression: \(\frac{x - 1}{{x}^{2} + 6 x + 9}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{x - 1}{{x}^{2} + 6 x + 9} = \frac{x - 1}{x^{2} + 6 x + 9} \)


Expanded

\[\frac{x - 1}{{x}^{2} + 6 x + 9} = \frac{x}{x^{2} + 6 x + 9} - \frac{1}{x^{2} + 6 x + 9}\]


Factored

\[\frac{x - 1}{{x}^{2} + 6 x + 9} = \frac{x - 1}{\left(x + 3\right)^{2}}\]