\[\dfrac{x^2-2x-15}{x^2-9}\]

asked by guest
on Jan 27, 2025 at 3:36 am



You asked:

Evaluate the expression: \(\frac{{x}^{2} - 2 x - 15}{{x}^{2} - 9}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{{x}^{2} - 2 x - 15}{{x}^{2} - 9} = \frac{x^{2} - 2 x - 15}{x^{2} - 9} \)

Expanded

\[\frac{{x}^{2} - 2 x - 15}{{x}^{2} - 9} = \frac{x^{2}}{x^{2} - 9} - \frac{2 x}{x^{2} - 9} - \frac{15}{x^{2} - 9}\]

Factored

\[\frac{{x}^{2} - 2 x - 15}{{x}^{2} - 9} = \frac{x - 5}{x - 3}\]

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