if 5^(x+2)= 15^(x+1) then x=?

asked by guest
on Sep 20, 2024 at 11:41 am



You asked:

Solve the equation \({5}^{x + 2} = {15}^{x + 1}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = - \frac{- 2 \log{\left(5 \right)} + \log{\left(15 \right)}}{- \log{\left(5 \right)} + \log{\left(15 \right)}} \approx 0.46497352\]

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