\int _{-\infty }^{+\infty }\:\frac{1}{\left(1+x^2\right)^2}dx

asked by guest
on Jan 01, 2025 at 1:04 am



You asked:

Evaluate the integral: ∫−∞∞1(1+x2)2dx\int_{-\infty}^{\infty}{\frac{1}{{\left( 1 + {x}^{2} \right)}^{2}}}dx

MathBot Answer:

Definite integral

∫−∞∞1(1+x2)2dx=π2≈1.57079632679489661923132169163975\int_{-\infty}^{\infty}{\frac{1}{{\left( 1 + {x}^{2} \right)}^{2}}}dx = \frac{\pi}{2} \approx 1.57079632679489661923132169163975

+ Submit Question