\sqrt((2x)^(2))-x^(2)
asked by guest on Nov 26, 2024 at 2:42 am
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MathBot Answer:
(2x)2−x2=−x2+2x2\sqrt{{\left( 2 x \right)}^{2}} - {x}^{2} = - x^{2} + 2 \sqrt{x^{2}}(2x)2−x2=−x2+2x2
If the variablexxx is real, then: −x2+2x2=−x2+2∣x∣- x^{2} + 2 \sqrt{x^{2}} = - x^{2} + 2 \left|{x}\right|−x2+2x2=−x2+2∣x∣