Simplify ((n+2)!n!)/((n-1)!)
asked by guest on Mar 15, 2025 at 3:06 pm
You asked:
MathBot Answer:
(n+2)!⋅n!(n−1)!=nΓ(n+3) \frac{\left( n + 2 \right)! \cdot n!}{\left( n - 1 \right)!} = n \Gamma\left(n + 3\right) (n−1)!(n+2)!⋅n!=nΓ(n+3)