(15/2)*n^2 + (21/2)*n + 8

factorize

asked by guest
on Nov 15, 2024 at 8:10 am



You asked:

Factor the expression: \(\displaystyle \frac{15}{2} \cdot {n}^{2} + \frac{21}{2} \cdot n + 8\)

MathBot Answer:

Factorization over the rational numbers:

\[\frac{15 n^{2} + 21 n + 16}{2}\]

Factorization over the complex numbers:

\[\frac{15 \left(n + \left(\frac{7}{10} - \frac{\sqrt{519} i}{30}\right)\right) \left(n + \left(\frac{7}{10} + \frac{\sqrt{519} i}{30}\right)\right)}{2}\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).