(x ^ 2 * y - 2x * y ^ 2) * dx + (x ^ 3 - 3x ^ 2 * y) * dy = 0

asked by guest
on Jul 26, 2024 at 10:47 pm



You asked:

Investigate the equation: \(\left({x}^{2} \cdot y - 2 x \cdot {y}^{2}\right) \cdot d x + \left({x}^{3} - 3 \cdot {x}^{2} \cdot y\right) \cdot d y = 0\).

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