(7a-3)^2
asked by guest on Feb 01, 2025 at 2:44 am
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MathBot Answer:
(7a−3)2=(7a−3)2\displaystyle {\left( 7 a - 3 \right)}^{2} = \left(7 a - 3\right)^{2} (7a−3)2=(7a−3)2
(7a−3)2=49a2−42a+9{\left( 7 a - 3 \right)}^{2} = 49 a^{2} - 42 a + 9(7a−3)2=49a2−42a+9