(x-3)-(x+2)+2(x-1)-5=0
You asked:
Solve the equation \(x - 3 - \left(x + 2\right) + 2 \cdot \left(x - 1\right) - 5 = 0\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = 6\]
\[\begin{aligned}x - 3 - \left(x + 2\right) + 2 \cdot \left(x - 1\right) - 5 &= 0\\2 x - 12 &= 0\\2 x &= 12\\x &= 6\end{aligned}\]