\lim _{x\to \infty }\left(\frac{sin\left(\pi +x\right)}{2x}\right)
You asked:
Evaluate the expression: \(\lim_{x \to \infty}{\frac{\sin\left( \pi + x \right)}{2 x}}\)
MathBot Answer:
\[\lim_{x \to \infty}{\frac{\sin\left( \pi + x \right)}{2 x}} = 0\]