σ = √[ (82-85.48)² + (83-85.48)² + (86-85.48)² + (87-85.48)² + (88-85.48)² + (88-85.48)² + (89-85.48)² + (92-85.48)² + (90-85.48)² + (89-85.48)² + (86-85.48)² + (85-85.48)² + (90-85.48)² + (80-85.48)² + (91-85.48)² + (80-85.48)² + (88-85.48)² + (80-85.48)² + (81-85.48)² + (84-85.48)² + (87-85.48)² + (85-85.48)² + (82-85.48)² + (85-85.48)² + (88-85.48)² + (88-85.48)² + (81-85.48)² + (86-85.48)² + (88-85.48)² + (84-85.48)² + (85-85.48)² + (84-85.48)² + (89-85.48)² + (81-85.48)² + (93-85.48)² + (91-85.48)² + (89-85.48)² + (85-85.48)² + (84-85.48)² + (87-85.48)² + (85-85.48)² + (80-85.48)² + (81-85.48)² + (83-85.48)² + (85-85.48)² + (80-85.48)² + (82-85.48)² + (85-85.48)² + (84-85.48)² + (88-85.48)² ] / 50

asked by guest
on Mar 22, 2025 at 11:12 am



You asked:

Solve the equation σ=(82−85.48)2+(83−85.48)2+(86−85.48)2+(87−85.48)2+(88−85.48)2+(88−85.48)2+(89−85.48)2+(92−85.48)2+(90−85.48)2+(89−85.48)2+(86−85.48)2+(85−85.48)2+(90−85.48)2+(80−85.48)2+(91−85.48)2+(80−85.48)2+(88−85.48)2+(80−85.48)2+(81−85.48)2+(84−85.48)2+(87−85.48)2+(85−85.48)2+(82−85.48)2+(85−85.48)2+(88−85.48)2+(88−85.48)2+(81−85.48)2+(86−85.48)2+(88−85.48)2+(84−85.48)2+(85−85.48)2+(84−85.48)2+(89−85.48)2+(81−85.48)2+(93−85.48)2+(91−85.48)2+(89−85.48)2+(85−85.48)2+(84−85.48)2+(87−85.48)2+(85−85.48)2+(80−85.48)2+(81−85.48)2+(83−85.48)2+(85−85.48)2+(80−85.48)2+(82−85.48)2+(85−85.48)2+(84−85.48)2+(88−85.48)250σ = \frac{\sqrt{{\left( 82 - 85.48 \right)}^{2} + {\left( 83 - 85.48 \right)}^{2} + {\left( 86 - 85.48 \right)}^{2} + {\left( 87 - 85.48 \right)}^{2} + {\left( 88 - 85.48 \right)}^{2} + {\left( 88 - 85.48 \right)}^{2} + {\left( 89 - 85.48 \right)}^{2} + {\left( 92 - 85.48 \right)}^{2} + {\left( 90 - 85.48 \right)}^{2} + {\left( 89 - 85.48 \right)}^{2} + {\left( 86 - 85.48 \right)}^{2} + {\left( 85 - 85.48 \right)}^{2} + {\left( 90 - 85.48 \right)}^{2} + {\left( 80 - 85.48 \right)}^{2} + {\left( 91 - 85.48 \right)}^{2} + {\left( 80 - 85.48 \right)}^{2} + {\left( 88 - 85.48 \right)}^{2} + {\left( 80 - 85.48 \right)}^{2} + {\left( 81 - 85.48 \right)}^{2} + {\left( 84 - 85.48 \right)}^{2} + {\left( 87 - 85.48 \right)}^{2} + {\left( 85 - 85.48 \right)}^{2} + {\left( 82 - 85.48 \right)}^{2} + {\left( 85 - 85.48 \right)}^{2} + {\left( 88 - 85.48 \right)}^{2} + {\left( 88 - 85.48 \right)}^{2} + {\left( 81 - 85.48 \right)}^{2} + {\left( 86 - 85.48 \right)}^{2} + {\left( 88 - 85.48 \right)}^{2} + {\left( 84 - 85.48 \right)}^{2} + {\left( 85 - 85.48 \right)}^{2} + {\left( 84 - 85.48 \right)}^{2} + {\left( 89 - 85.48 \right)}^{2} + {\left( 81 - 85.48 \right)}^{2} + {\left( 93 - 85.48 \right)}^{2} + {\left( 91 - 85.48 \right)}^{2} + {\left( 89 - 85.48 \right)}^{2} + {\left( 85 - 85.48 \right)}^{2} + {\left( 84 - 85.48 \right)}^{2} + {\left( 87 - 85.48 \right)}^{2} + {\left( 85 - 85.48 \right)}^{2} + {\left( 80 - 85.48 \right)}^{2} + {\left( 81 - 85.48 \right)}^{2} + {\left( 83 - 85.48 \right)}^{2} + {\left( 85 - 85.48 \right)}^{2} + {\left( 80 - 85.48 \right)}^{2} + {\left( 82 - 85.48 \right)}^{2} + {\left( 85 - 85.48 \right)}^{2} + {\left( 84 - 85.48 \right)}^{2} + {\left( 88 - 85.48 \right)}^{2}}}{50} for the variable σσ.

MathBot Answer:

The solution is: σ=14862250≈0.48763921σ = \frac{\sqrt{14862}}{250} \approx 0.48763921

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