12.5%of80kg
You asked:
Evaluate the expression: \(\frac{12.5}{100} \cdot 80 k g\)
MathBot Answer:
Evaluated
\(\displaystyle \frac{12.5}{100} \cdot 80 k g = 10 g k \)
Expanded
\[\frac{12.5}{100} \cdot 80 k g = 10 g k\]
12.5%of80kg
You asked:
MathBot Answer:
\(\displaystyle \frac{12.5}{100} \cdot 80 k g = 10 g k \)
\[\frac{12.5}{100} \cdot 80 k g = 10 g k\]