x^3+1/X^3=198 FIND X
asked by guest on Jan 15, 2025 at 11:00 am
You asked:
MathBot Answer:
X=−1x3−1983X=−−1x3−19832−3i−1x3−19832X=−−1x3−19832+3i−1x3−19832\begin{aligned}X &= \sqrt[3]{- \frac{1}{x^{3} - 198}}\\X &= - \frac{\sqrt[3]{- \frac{1}{x^{3} - 198}}}{2} - \frac{\sqrt{3} i \sqrt[3]{- \frac{1}{x^{3} - 198}}}{2}\\X &= - \frac{\sqrt[3]{- \frac{1}{x^{3} - 198}}}{2} + \frac{\sqrt{3} i \sqrt[3]{- \frac{1}{x^{3} - 198}}}{2}\end{aligned}XXX=3−x3−1981=−23−x3−1981−23i3−x3−1981=−23−x3−1981+23i3−x3−1981 and X≠0X \neq 0X=0