y′′+6y′+9y=3x

asked by guest
on Nov 18, 2024 at 2:34 am



You asked:

Investigate the equation: \(y^{\prime \prime} + 6 \cdot y^{\prime} + 9 y = 3 x\).

MathBot Answer:

\[y{\left(x \right)} = - \frac{2}{9} + \frac{x}{3} + \left(C_{2} x + C_{1}\right) e^{- 3 x}\]

\(C_{1}\), \(C_{2}\) are arbitrary constants.

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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