(3.06202+1)^2=4p(10.05-8.8)

asked by guest
on Mar 17, 2025 at 3:26 am



You asked:

Solve the equation (3.06202+1)2=4⋅p(10.05−8.8){\left( 3.06202 + 1 \right)}^{2} = 4 \cdot p\left( 10.05 - 8.8 \right) for the variable pp.

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